Base | Representation |
---|---|
bin | 1100001100101011101111… |
… | …1001110110100110010111 |
3 | 1202111011211011012202121011 |
4 | 3003022323321312212113 |
5 | 3224220324320401401 |
6 | 44305223432233051 |
7 | 2552662602264232 |
oct | 303127371664627 |
9 | 52434734182534 |
10 | 13412040403351 |
11 | 430101817a367 |
12 | 160741523b787 |
13 | 763999936585 |
14 | 345209322419 |
15 | 183d28132451 |
hex | c32bbe76997 |
13412040403351 has 8 divisors (see below), whose sum is σ = 13724020323200. Its totient is φ = 13100063756472.
The previous prime is 13412040403343. The next prime is 13412040403367. The reversal of 13412040403351 is 15330404021431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13412040403351 - 23 = 13412040403343 is a prime.
It is a super-2 number, since 2×134120404033512 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13412040403381) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8762350 + ... + 10178548.
It is an arithmetic number, because the mean of its divisors is an integer number (1715502540400).
Almost surely, 213412040403351 is an apocalyptic number.
13412040403351 is a deficient number, since it is larger than the sum of its proper divisors (311979919849).
13412040403351 is a wasteful number, since it uses less digits than its factorization.
13412040403351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1636485.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13412040403351 its reverse (15330404021431), we get a palindrome (28742444424782).
The spelling of 13412040403351 in words is "thirteen trillion, four hundred twelve billion, forty million, four hundred three thousand, three hundred fifty-one".
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