13412044532031 has 4 divisors (see below), whose sum is σ = 17882726042712. Its totient is φ = 8941363021352.

The previous prime is 13412044532023. The next prime is 13412044532063. The reversal of 13412044532031 is 13023544021431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13412044532031 - 2³ = 13412044532023 is a prime.

It is a super-2 number, since 2×13412044532031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13412044531983 and 13412044532001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13412044032031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2235340755336 + ... + 2235340755341.

It is an arithmetic number, because the mean of its divisors is an integer number (4470681510678).

Almost surely, 2^{13412044532031} is an apocalyptic number.

13412044532031 is a deficient number, since it is larger than the sum of its proper divisors (4470681510681).

13412044532031 is an equidigital number, since it uses as much as digits as its factorization.

13412044532031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4470681510680.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 13412044532031 its reverse (13023544021431), we get a palindrome (26435588553462).

The spelling of 13412044532031 in words is "thirteen trillion, four hundred twelve billion, forty-four million, five hundred thirty-two thousand, thirty-one".