Base | Representation |
---|---|
bin | 11110011111101110000111… |
… | …101011101111110100111011 |
3 | 122120212212022102210100201100 |
4 | 132133232013223233310323 |
5 | 120034420224324110233 |
6 | 1153130234332222443 |
7 | 40151636603015460 |
oct | 3637560753576473 |
9 | 576785272710640 |
10 | 134121220144443 |
11 | 3980a543269554 |
12 | 1306171130aa23 |
13 | 59ab76629352c |
14 | 25197048d9667 |
15 | 1078c026c3813 |
hex | 79fb87aefd3b |
134121220144443 has 24 divisors (see below), whose sum is σ = 221542541462528. Its totient is φ = 76593591636912.
The previous prime is 134121220144441. The next prime is 134121220144517. The reversal of 134121220144443 is 344441022121431.
134121220144443 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 2 + 1 + 2 + 201 + 4 + 4 + 443 = 666.
It is not a de Polignac number, because 134121220144443 - 21 = 134121220144441 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 134121220144398 and 134121220144407.
It is not an unprimeable number, because it can be changed into a prime (134121220144441) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 654140971 + ... + 654345972.
Almost surely, 2134121220144443 is an apocalyptic number.
134121220144443 is a deficient number, since it is larger than the sum of its proper divisors (87421321318085).
134121220144443 is a wasteful number, since it uses less digits than its factorization.
134121220144443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1308488583 (or 1308488580 counting only the distinct ones).
The product of its (nonzero) digits is 73728, while the sum is 36.
Adding to 134121220144443 its reverse (344441022121431), we get a palindrome (478562242265874).
The spelling of 134121220144443 in words is "one hundred thirty-four trillion, one hundred twenty-one billion, two hundred twenty million, one hundred forty-four thousand, four hundred forty-three".
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