134126444621431 has 4 divisors (see below), whose sum is σ = 134126824365864. Its totient is φ = 134126064877000.

The previous prime is 134126444621387. The next prime is 134126444621447.

134126444621431 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134126444621431 - 2³⁹ = 133576688807543 is a prime.

It is a super-3 number, since 3×134126444621431³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134126444621461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189341920 + ... + 190048981.

It is an arithmetic number, because the mean of its divisors is an integer number (33531706091466).

Almost surely, 2^{134126444621431} is an apocalyptic number.

134126444621431 is a deficient number, since it is larger than the sum of its proper divisors (379744433).

134126444621431 is an equidigital number, since it uses as much as digits as its factorization.

134126444621431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 379744432.

The product of its digits is 1327104, while the sum is 46.

The spelling of 134126444621431 in words is "one hundred thirty-four trillion, one hundred twenty-six billion, four hundred forty-four million, six hundred twenty-one thousand, four hundred thirty-one".