1341272825141 has 4 divisors (see below), whose sum is σ = 1350155426784. Its totient is φ = 1332390223500.

The previous prime is 1341272825119. The next prime is 1341272825149. The reversal of 1341272825141 is 1415282721431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1341272825141 - 2¹⁰ = 1341272824117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341272825149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4441300595 + ... + 4441300896.

It is an arithmetic number, because the mean of its divisors is an integer number (337538856696).

Almost surely, 2^{1341272825141} is an apocalyptic number.

It is an amenable number.

1341272825141 is a deficient number, since it is larger than the sum of its proper divisors (8882601643).

1341272825141 is an equidigital number, since it uses as much as digits as its factorization.

1341272825141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8882601642.

The product of its digits is 107520, while the sum is 41.

The spelling of 1341272825141 in words is "one trillion, three hundred forty-one billion, two hundred seventy-two million, eight hundred twenty-five thousand, one hundred forty-one".