Base | Representation |
---|---|
bin | 10011100001001010001… |
… | …100110001110010100111 |
3 | 11202020001201220102112112 |
4 | 103201022030301302213 |
5 | 133433412303110012 |
6 | 2504101214511235 |
7 | 165622015333202 |
oct | 23411214616247 |
9 | 4666051812475 |
10 | 1341274660007 |
11 | 477916640157 |
12 | 197b4620551b |
13 | 99635281a99 |
14 | 48cbd15c939 |
15 | 24d52794122 |
hex | 1384a331ca7 |
1341274660007 has 4 divisors (see below), whose sum is σ = 1341280707960. Its totient is φ = 1341268612056.
The previous prime is 1341274659971. The next prime is 1341274660009. The reversal of 1341274660007 is 7000664721431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1341274660007 - 26 = 1341274659943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1341274660009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2678132 + ... + 3139257.
It is an arithmetic number, because the mean of its divisors is an integer number (335320176990).
Almost surely, 21341274660007 is an apocalyptic number.
1341274660007 is a deficient number, since it is larger than the sum of its proper divisors (6047953).
1341274660007 is an equidigital number, since it uses as much as digits as its factorization.
1341274660007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6047952.
The product of its (nonzero) digits is 169344, while the sum is 41.
The spelling of 1341274660007 in words is "one trillion, three hundred forty-one billion, two hundred seventy-four million, six hundred sixty thousand, seven".
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