13413140011040 has 768 divisors, whose sum is σ = 42935153393664. Its totient is φ = 3835419033600.

The previous prime is 13413140011039. The next prime is 13413140011043. The reversal of 13413140011040 is 4011004131431.

It is a Harshad number since it is a multiple of its sum of digits (23).

It is a junction number, because it is equal to n+sod(n) for n = 13413140010997 and 13413140011015.

It is not an unprimeable number, because it can be changed into a prime (13413140011043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 992603324 + ... + 992616836.

It is an arithmetic number, because the mean of its divisors is an integer number (55905147648).

Almost surely, 2^{13413140011040} is an apocalyptic number.

13413140011040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13413140011040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21467576696832).

13413140011040 is an abundant number, since it is smaller than the sum of its proper divisors (29522013382624).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13413140011040 is a wasteful number, since it uses less digits than its factorization.

13413140011040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13713 (or 13705 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13413140011040 its reverse (4011004131431), we get a palindrome (17424144142471).

The spelling of 13413140011040 in words is "thirteen trillion, four hundred thirteen billion, one hundred forty million, eleven thousand, forty".