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1341315255453 = 3447105085151
BaseRepresentation
bin10011100001001100100…
…111101000110010011101
311202020011120021220000120
4103201030213220302131
5133434003201133303
62504105224545153
7165623020361235
oct23411447506235
94666146256016
101341315255453
11477937548108
12197b579221b9
13996407c6664
1448cc46c8cc5
1524d56112553
hex1384c9e8c9d

1341315255453 has 4 divisors (see below), whose sum is σ = 1788420340608. Its totient is φ = 894210170300.

The previous prime is 1341315255437. The next prime is 1341315255487. The reversal of 1341315255453 is 3545525131431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1341315255453 - 24 = 1341315255437 is a prime.

It is a super-2 number, since 2×13413152554532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341315255853) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223552542573 + ... + 223552542578.

It is an arithmetic number, because the mean of its divisors is an integer number (447105085152).

Almost surely, 21341315255453 is an apocalyptic number.

It is an amenable number.

1341315255453 is a deficient number, since it is larger than the sum of its proper divisors (447105085155).

1341315255453 is an equidigital number, since it uses as much as digits as its factorization.

1341315255453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 447105085154.

The product of its digits is 540000, while the sum is 42.

The spelling of 1341315255453 in words is "one trillion, three hundred forty-one billion, three hundred fifteen million, two hundred fifty-five thousand, four hundred fifty-three".

Divisors: 1 3 447105085151 1341315255453