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134132425301 = 719161775043
BaseRepresentation
bin111110011101011101…
…0100110001001010101
3110211012220211012102202
41330322322212021111
54144200400102201
6141341455214245
712455632542350
oct1747272461125
9424186735382
10134132425301
1151981291456
1221bb4817385
13c8580808c4
1466c6251297
153750a45c6b
hex1f3aea6255

134132425301 has 4 divisors (see below), whose sum is σ = 153294200352. Its totient is φ = 114970650252.

The previous prime is 134132425291. The next prime is 134132425313. The reversal of 134132425301 is 103524231431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134132425301 - 210 = 134132424277 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134132425321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9580887515 + ... + 9580887528.

It is an arithmetic number, because the mean of its divisors is an integer number (38323550088).

Almost surely, 2134132425301 is an apocalyptic number.

It is an amenable number.

134132425301 is a deficient number, since it is larger than the sum of its proper divisors (19161775051).

134132425301 is an equidigital number, since it uses as much as digits as its factorization.

134132425301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19161775050.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 134132425301 its reverse (103524231431), we get a palindrome (237656656732).

The spelling of 134132425301 in words is "one hundred thirty-four billion, one hundred thirty-two million, four hundred twenty-five thousand, three hundred one".

Divisors: 1 7 19161775043 134132425301