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1341324331042 = 24315596794547
BaseRepresentation
bin10011100001001101001…
…010010000100000100010
311202020012012100222101111
4103201031022100200202
5133434013012043132
62504110151253534
7165623160460543
oct23411512204042
94666165328344
101341324331042
114779416867a3
12197b5a97a2aa
1399642653527
1448cc59ac4ca
1524d56d06647
hex1384d290822

1341324331042 has 8 divisors (see below), whose sum is σ = 2058776880336. Its totient is φ = 655065370932.

The previous prime is 1341324331033. The next prime is 1341324331093. The reversal of 1341324331042 is 2401334231431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13413243310422 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1341324330995 and 1341324331013.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7798397188 + ... + 7798397359.

It is an arithmetic number, because the mean of its divisors is an integer number (257347110042).

Almost surely, 21341324331042 is an apocalyptic number.

1341324331042 is a deficient number, since it is larger than the sum of its proper divisors (717452549294).

1341324331042 is a wasteful number, since it uses less digits than its factorization.

1341324331042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15596794592.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1341324331042 its reverse (2401334231431), we get a palindrome (3742658562473).

The spelling of 1341324331042 in words is "one trillion, three hundred forty-one billion, three hundred twenty-four million, three hundred thirty-one thousand, forty-two".

Divisors: 1 2 43 86 15596794547 31193589094 670662165521 1341324331042