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13413411034013 = 34981383448473
BaseRepresentation
bin1100001100110000110110…
…0110011001001110011101
31202111022100200022000101202
43003030031212121032131
53224231131211042023
644310011433445245
72553041554406054
oct303141546311635
952438320260352
1013413411034013
114301660929481
121607738270825
13763b578a1133
143452d938b39b
15183da8625128
hexc330d99939d

13413411034013 has 4 divisors (see below), whose sum is σ = 13413794517468. Its totient is φ = 13413027550560.

The previous prime is 13413411033989. The next prime is 13413411034087. The reversal of 13413411034013 is 31043011431431.

13413411034013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2449484796889 + 10963926237124 = 1565083^2 + 3311182^2 .

It is a cyclic number.

It is not a de Polignac number, because 13413411034013 - 224 = 13413394256797 is a prime.

It is a super-3 number, since 3×134134110340133 (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13413411034613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191689256 + ... + 191759217.

It is an arithmetic number, because the mean of its divisors is an integer number (3353448629367).

Almost surely, 213413411034013 is an apocalyptic number.

It is an amenable number.

13413411034013 is a deficient number, since it is larger than the sum of its proper divisors (383483455).

13413411034013 is an equidigital number, since it uses as much as digits as its factorization.

13413411034013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 383483454.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13413411034013 its reverse (31043011431431), we get a palindrome (44456422465444).

The spelling of 13413411034013 in words is "thirteen trillion, four hundred thirteen billion, four hundred eleven million, thirty-four thousand, thirteen".

Divisors: 1 34981 383448473 13413411034013