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134134113151 = 503266668217
BaseRepresentation
bin111110011101100000…
…1000010001101111111
3110211020000222221201201
41330323001002031333
54144201313110101
6141341555320331
712455653102243
oct1747301021577
9424200887651
10134134113151
1151982234575
1221bb52b00a7
13c858521c2c
1466c6570423
153750c7ae01
hex1f3b04237f

134134113151 has 4 divisors (see below), whose sum is σ = 134400781872. Its totient is φ = 133867444432.

The previous prime is 134134113121. The next prime is 134134113251. The reversal of 134134113151 is 151311431431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134134113151 - 213 = 134134104959 is a prime.

It is a super-2 number, since 2×1341341131512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134134113121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133333606 + ... + 133334611.

It is an arithmetic number, because the mean of its divisors is an integer number (33600195468).

Almost surely, 2134134113151 is an apocalyptic number.

134134113151 is a deficient number, since it is larger than the sum of its proper divisors (266668721).

134134113151 is an equidigital number, since it uses as much as digits as its factorization.

134134113151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 266668720.

The product of its digits is 2160, while the sum is 28.

Adding to 134134113151 its reverse (151311431431), we get a palindrome (285445544582).

The spelling of 134134113151 in words is "one hundred thirty-four billion, one hundred thirty-four million, one hundred thirteen thousand, one hundred fifty-one".

Divisors: 1 503 266668217 134134113151