Base | Representation |
---|---|
bin | 10011100001010001101… |
… | …110110011101111101111 |
3 | 11202020101112200020210222 |
4 | 103201101232303233233 |
5 | 133434142130141143 |
6 | 2504121531121555 |
7 | 165625111360631 |
oct | 23412156635757 |
9 | 4666345606728 |
10 | 1341401021423 |
11 | 4779809a7381 |
12 | 197b805a32bb |
13 | 996554c5358 |
14 | 48cd1c52a51 |
15 | 24d5d904768 |
hex | 13851bb3bef |
1341401021423 has 4 divisors (see below), whose sum is σ = 1350284472048. Its totient is φ = 1332517570800.
The previous prime is 1341401021399. The next prime is 1341401021449. The reversal of 1341401021423 is 3241201041431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1341401021423 - 214 = 1341401005039 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1341401021392 and 1341401021401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1341401021453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4441725086 + ... + 4441725387.
It is an arithmetic number, because the mean of its divisors is an integer number (337571118012).
Almost surely, 21341401021423 is an apocalyptic number.
1341401021423 is a deficient number, since it is larger than the sum of its proper divisors (8883450625).
1341401021423 is an equidigital number, since it uses as much as digits as its factorization.
1341401021423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8883450624.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 1341401021423 its reverse (3241201041431), we get a palindrome (4582602062854).
The spelling of 1341401021423 in words is "one trillion, three hundred forty-one billion, four hundred one million, twenty-one thousand, four hundred twenty-three".
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