Base | Representation |
---|---|
bin | 111110011101101100… |
… | …0010011101101100001 |
3 | 110211020110110220200021 |
4 | 1330323120103231201 |
5 | 4144204343322423 |
6 | 141342334153441 |
7 | 12456056002303 |
oct | 1747330235541 |
9 | 424213426607 |
10 | 134140214113 |
11 | 51985721294 |
12 | 21bb7352881 |
13 | c859879b79 |
14 | 66c72bb973 |
15 | 375158395d |
hex | 1f3b613b61 |
134140214113 has 4 divisors (see below), whose sum is σ = 135647407620. Its totient is φ = 132633020608.
The previous prime is 134140214101. The next prime is 134140214191. The reversal of 134140214113 is 311412041431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 49385283984 + 84754930129 = 222228^2 + 291127^2 .
It is a cyclic number.
It is not a de Polignac number, because 134140214113 - 25 = 134140214081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134140214513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 753596620 + ... + 753596797.
It is an arithmetic number, because the mean of its divisors is an integer number (33911851905).
Almost surely, 2134140214113 is an apocalyptic number.
It is an amenable number.
134140214113 is a deficient number, since it is larger than the sum of its proper divisors (1507193507).
134140214113 is an equidigital number, since it uses as much as digits as its factorization.
134140214113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1507193506.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 134140214113 its reverse (311412041431), we get a palindrome (445552255544).
The spelling of 134140214113 in words is "one hundred thirty-four billion, one hundred forty million, two hundred fourteen thousand, one hundred thirteen".
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