Base | Representation |
---|---|
bin | 10011100001010001111… |
… | …000000010111110011101 |
3 | 11202020101201020021201202 |
4 | 103201101320002332131 |
5 | 133434143240134401 |
6 | 2504122055045245 |
7 | 165625141065131 |
oct | 23412170027635 |
9 | 4666351207652 |
10 | 1341403443101 |
11 | 477982300867 |
12 | 197b81370825 |
13 | 99655b626b7 |
14 | 48cd22c33c1 |
15 | 24d5dc3206b |
hex | 13851e02f9d |
1341403443101 has 4 divisors (see below), whose sum is σ = 1358383233600. Its totient is φ = 1324423652604.
The previous prime is 1341403443091. The next prime is 1341403443157. The reversal of 1341403443101 is 1013443041431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1341403443101 - 238 = 1066525536157 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1341403443701) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8489895131 + ... + 8489895288.
It is an arithmetic number, because the mean of its divisors is an integer number (339595808400).
Almost surely, 21341403443101 is an apocalyptic number.
It is an amenable number.
1341403443101 is a deficient number, since it is larger than the sum of its proper divisors (16979790499).
1341403443101 is an equidigital number, since it uses as much as digits as its factorization.
1341403443101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16979790498.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1341403443101 its reverse (1013443041431), we get a palindrome (2354846484532).
The spelling of 1341403443101 in words is "one trillion, three hundred forty-one billion, four hundred three million, four hundred forty-three thousand, one hundred one".
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