Base | Representation |
---|---|
bin | 1100001100110011111100… |
… | …1000101010001111111011 |
3 | 1202111101111121002112220121 |
4 | 3003030333020222033323 |
5 | 3224234331434201334 |
6 | 44310230122234111 |
7 | 2553101265351442 |
oct | 303147710521773 |
9 | 52441447075817 |
10 | 13414242100219 |
11 | 4301a47a58854 |
12 | 160792a655937 |
13 | 763c5ab1039c |
14 | 3453778c1d59 |
15 | 183e06586db4 |
hex | c333f22a3fb |
13414242100219 has 4 divisors (see below), whose sum is σ = 13446104908480. Its totient is φ = 13382379291960.
The previous prime is 13414242100211. The next prime is 13414242100241. The reversal of 13414242100219 is 91200124241431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13414242100219 - 23 = 13414242100211 is a prime.
It is a super-2 number, since 2×134142421002192 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13414242100211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15931403499 + ... + 15931404340.
It is an arithmetic number, because the mean of its divisors is an integer number (3361526227120).
Almost surely, 213414242100219 is an apocalyptic number.
13414242100219 is a deficient number, since it is larger than the sum of its proper divisors (31862808261).
13414242100219 is an equidigital number, since it uses as much as digits as its factorization.
13414242100219 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31862808260.
The product of its (nonzero) digits is 13824, while the sum is 34.
The spelling of 13414242100219 in words is "thirteen trillion, four hundred fourteen billion, two hundred forty-two million, one hundred thousand, two hundred nineteen".
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