1341441313042 has 4 divisors (see below), whose sum is σ = 2012161969566. Its totient is φ = 670720656520.

The previous prime is 1341441312947. The next prime is 1341441313063. The reversal of 1341441313042 is 2403131441431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1289494242481 + 51947070561 = 1135559^2 + 227919^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1341441312995 and 1341441313013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335360328259 + ... + 335360328262.

Almost surely, 2^{1341441313042} is an apocalyptic number.

1341441313042 is a deficient number, since it is larger than the sum of its proper divisors (670720656524).

1341441313042 is an equidigital number, since it uses as much as digits as its factorization.

1341441313042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 670720656523.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1341441313042 its reverse (2403131441431), we get a palindrome (3744572754473).

The spelling of 1341441313042 in words is "one trillion, three hundred forty-one billion, four hundred forty-one million, three hundred thirteen thousand, forty-two".