13414535433343 has 4 divisors (see below), whose sum is σ = 14634038654568. Its totient is φ = 12195032212120.

The previous prime is 13414535433331. The next prime is 13414535433347. The reversal of 13414535433343 is 34333453541431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13414535433343 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13414535433293 and 13414535433302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13414535433347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 609751610596 + ... + 609751610617.

It is an arithmetic number, because the mean of its divisors is an integer number (3658509663642).

Almost surely, 2^{13414535433343} is an apocalyptic number.

13414535433343 is a deficient number, since it is larger than the sum of its proper divisors (1219503221225).

13414535433343 is a wasteful number, since it uses less digits than its factorization.

13414535433343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1219503221224.

The product of its digits is 4665600, while the sum is 46.

Adding to 13414535433343 its reverse (34333453541431), we get a palindrome (47747988974774).

The spelling of 13414535433343 in words is "thirteen trillion, four hundred fourteen billion, five hundred thirty-five million, four hundred thirty-three thousand, three hundred forty-three".