Base | Representation |
---|---|
bin | 1100001100110101110100… |
… | …0011100000110101110011 |
3 | 1202111102210120122010111021 |
4 | 3003031131003200311303 |
5 | 3224241343440124233 |
6 | 44310352013200311 |
7 | 2553116602120645 |
oct | 303153503406563 |
9 | 52442716563437 |
10 | 13414744067443 |
11 | 43021853391a4 |
12 | 1607a4a790097 |
13 | 76400ab03a04 |
14 | 3453c442a895 |
15 | 183e3568ce2d |
hex | c335d0e0d73 |
13414744067443 has 4 divisors (see below), whose sum is σ = 13667852446128. Its totient is φ = 13161635688760.
The previous prime is 13414744067437. The next prime is 13414744067447. The reversal of 13414744067443 is 34476044741431.
13414744067443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13414744067443 - 29 = 13414744066931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13414744067447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126554189263 + ... + 126554189368.
It is an arithmetic number, because the mean of its divisors is an integer number (3416963111532).
Almost surely, 213414744067443 is an apocalyptic number.
13414744067443 is a deficient number, since it is larger than the sum of its proper divisors (253108378685).
13414744067443 is an equidigital number, since it uses as much as digits as its factorization.
13414744067443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 253108378684.
The product of its (nonzero) digits is 10838016, while the sum is 52.
The spelling of 13414744067443 in words is "thirteen trillion, four hundred fourteen billion, seven hundred forty-four million, sixty-seven thousand, four hundred forty-three".
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