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1341514534403 = 3692336332761
BaseRepresentation
bin10011100001011000011…
…111110100111000000011
311202020200110021022100102
4103201120133310320003
5133434410210100103
62504141104113015
7165630660253361
oct23413037647003
94666613238312
101341514534403
11477a29a8835a
12197bb260576b
1399672b8a6b4
1448d02d60631
1524d68877e88
hex138587f4e03

1341514534403 has 4 divisors (see below), whose sum is σ = 1341550904088. Its totient is φ = 1341478164720.

The previous prime is 1341514534363. The next prime is 1341514534411. The reversal of 1341514534403 is 3044354151431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1341514534403 is a prime.

It is a super-2 number, since 2×13415145344032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1341514536403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18129458 + ... + 18203303.

It is an arithmetic number, because the mean of its divisors is an integer number (335387726022).

Almost surely, 21341514534403 is an apocalyptic number.

1341514534403 is a deficient number, since it is larger than the sum of its proper divisors (36369685).

1341514534403 is an equidigital number, since it uses as much as digits as its factorization.

1341514534403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36369684.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 1341514534403 its reverse (3044354151431), we get a palindrome (4385868685834).

The spelling of 1341514534403 in words is "one trillion, three hundred forty-one billion, five hundred fourteen million, five hundred thirty-four thousand, four hundred three".

Divisors: 1 36923 36332761 1341514534403