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1341612335554 = 2670806167777
BaseRepresentation
bin10011100001011110010…
…100111010000111000010
311202020221021022010022021
4103201132110322013002
5133440110224214204
62504154520232054
7165633255460051
oct23413624720702
94666837263267
101341612335554
11477a7a207857
1219801b30b62a
139968a2113ba
1448d11d3c398
1524d72246154
hex1385e53a1c2

1341612335554 has 4 divisors (see below), whose sum is σ = 2012418503334. Its totient is φ = 670806167776.

The previous prime is 1341612335537. The next prime is 1341612335639. The reversal of 1341612335554 is 4555332161431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1011177058329 + 330435277225 = 1005573^2 + 574835^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 1341612335554.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335403083887 + ... + 335403083890.

Almost surely, 21341612335554 is an apocalyptic number.

1341612335554 is a deficient number, since it is larger than the sum of its proper divisors (670806167780).

1341612335554 is an equidigital number, since it uses as much as digits as its factorization.

1341612335554 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 670806167779.

The product of its digits is 648000, while the sum is 43.

Adding to 1341612335554 its reverse (4555332161431), we get a palindrome (5896944496985).

The spelling of 1341612335554 in words is "one trillion, three hundred forty-one billion, six hundred twelve million, three hundred thirty-five thousand, five hundred fifty-four".

Divisors: 1 2 670806167777 1341612335554