Base | Representation |
---|---|
bin | 11000111111011011… |
… | …11000000110010001 |
3 | 1021122001111022212212 |
4 | 30133231320012101 |
5 | 204434224144331 |
6 | 10055205201505 |
7 | 653325542516 |
oct | 143755700621 |
9 | 37561438785 |
10 | 13417021841 |
11 | 5765617103 |
12 | 2725400295 |
13 | 135a8c2ca2 |
14 | 913cc130d |
15 | 537d78d2b |
hex | 31fb78191 |
13417021841 has 4 divisors (see below), whose sum is σ = 13417481712. Its totient is φ = 13416561972.
The previous prime is 13417021831. The next prime is 13417021879. The reversal of 13417021841 is 14812071431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14812071431 = 67 ⋅221075693.
It is a cyclic number.
It is not a de Polignac number, because 13417021841 - 210 = 13417020817 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13417021798 and 13417021807.
It is not an unprimeable number, because it can be changed into a prime (13417021831) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182975 + ... + 245588.
It is an arithmetic number, because the mean of its divisors is an integer number (3354370428).
Almost surely, 213417021841 is an apocalyptic number.
It is an amenable number.
13417021841 is a deficient number, since it is larger than the sum of its proper divisors (459871).
13417021841 is an equidigital number, since it uses as much as digits as its factorization.
13417021841 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 459870.
The product of its (nonzero) digits is 5376, while the sum is 32.
The spelling of 13417021841 in words is "thirteen billion, four hundred seventeen million, twenty-one thousand, eight hundred forty-one".
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