134202000141331 has 4 divisors (see below), whose sum is σ = 134540040444352. Its totient is φ = 133863959838312.

The previous prime is 134202000141301. The next prime is 134202000141431. The reversal of 134202000141331 is 133141000202431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134202000141331 - 2¹³ = 134202000133139 is a prime.

It is a super-2 number, since 2×134202000141331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134202000141296 and 134202000141305.

It is not an unprimeable number, because it can be changed into a prime (134202000141301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169020150915 + ... + 169020151708.

It is an arithmetic number, because the mean of its divisors is an integer number (33635010111088).

Almost surely, 2^{134202000141331} is an apocalyptic number.

134202000141331 is a deficient number, since it is larger than the sum of its proper divisors (338040303021).

134202000141331 is an equidigital number, since it uses as much as digits as its factorization.

134202000141331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 338040303020.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 134202000141331 its reverse (133141000202431), we get a palindrome (267343000343762).

The spelling of 134202000141331 in words is "one hundred thirty-four trillion, two hundred two billion, one hundred forty-one thousand, three hundred thirty-one".