Base | Representation |
---|---|
bin | 11000111111110100… |
… | …01101001100110111 |
3 | 1021122021120112120201 |
4 | 30133322031030313 |
5 | 204441041112012 |
6 | 10055402341331 |
7 | 653365163656 |
oct | 143772151467 |
9 | 37567515521 |
10 | 13420254007 |
11 | 5767424516 |
12 | 27264ba847 |
13 | 135b485204 |
14 | 9144c319d |
15 | 5382b6857 |
hex | 31fe8d337 |
13420254007 has 4 divisors (see below), whose sum is σ = 13590130720. Its totient is φ = 13250377296.
The previous prime is 13420253999. The next prime is 13420254011. The reversal of 13420254007 is 70045202431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13420254007 - 23 = 13420253999 is a prime.
It is a super-2 number, since 2×134202540072 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13420254017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84938238 + ... + 84938395.
It is an arithmetic number, because the mean of its divisors is an integer number (3397532680).
Almost surely, 213420254007 is an apocalyptic number.
13420254007 is a deficient number, since it is larger than the sum of its proper divisors (169876713).
13420254007 is an equidigital number, since it uses as much as digits as its factorization.
13420254007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 169876712.
The product of its (nonzero) digits is 6720, while the sum is 28.
Adding to 13420254007 its reverse (70045202431), we get a palindrome (83465456438).
The spelling of 13420254007 in words is "thirteen billion, four hundred twenty million, two hundred fifty-four thousand, seven".
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