13420324404113 has 4 divisors (see below), whose sum is σ = 14640353895408. Its totient is φ = 12200294912820.

The previous prime is 13420324404079. The next prime is 13420324404143. The reversal of 13420324404113 is 31140442302431.

13420324404113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13420324404113 is a prime.

It is a super-2 number, since 2×13420324404113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13420324404113.

It is not an unprimeable number, because it can be changed into a prime (13420324404143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 610014745631 + ... + 610014745652.

It is an arithmetic number, because the mean of its divisors is an integer number (3660088473852).

Almost surely, 2^{13420324404113} is an apocalyptic number.

It is an amenable number.

13420324404113 is a deficient number, since it is larger than the sum of its proper divisors (1220029491295).

13420324404113 is a wasteful number, since it uses less digits than its factorization.

13420324404113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1220029491294.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13420324404113 its reverse (31140442302431), we get a palindrome (44560766706544).

The spelling of 13420324404113 in words is "thirteen trillion, four hundred twenty billion, three hundred twenty-four million, four hundred four thousand, one hundred thirteen".