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1342043323 = 5922746497
BaseRepresentation
bin100111111111101…
…1111010010111011
310110112021212100021
41033333133102323
510222030341243
6341100351311
745154115515
oct11777372273
93415255307
101342043323
11629604015
12315545537
1318506889a
14ca346bb5
157cc476ed
hex4ffdf4bb

1342043323 has 4 divisors (see below), whose sum is σ = 1364789880. Its totient is φ = 1319296768.

The previous prime is 1342043303. The next prime is 1342043333. The reversal of 1342043323 is 3233402431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1342043323 - 29 = 1342042811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1342043303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11373190 + ... + 11373307.

It is an arithmetic number, because the mean of its divisors is an integer number (341197470).

Almost surely, 21342043323 is an apocalyptic number.

1342043323 is a deficient number, since it is larger than the sum of its proper divisors (22746557).

1342043323 is an equidigital number, since it uses as much as digits as its factorization.

1342043323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22746556.

The product of its (nonzero) digits is 5184, while the sum is 25.

The square root of 1342043323 is about 36633.9094692336. The cubic root of 1342043323 is about 1103.0338624832.

Adding to 1342043323 its reverse (3233402431), we get a palindrome (4575445754).

The spelling of 1342043323 in words is "one billion, three hundred forty-two million, forty-three thousand, three hundred twenty-three".

Divisors: 1 59 22746497 1342043323