Base | Representation |
---|---|
bin | 111110011111100111… |
… | …1101011100011100111 |
3 | 110211101222111111100211 |
4 | 1330333033223203213 |
5 | 4144322443430401 |
6 | 141353012120251 |
7 | 12460504125304 |
oct | 1747717534347 |
9 | 424358444324 |
10 | 134205061351 |
11 | 51a09292a49 |
12 | 22015006087 |
13 | c86a13320a |
14 | 66d1b5c0ab |
15 | 37570e2951 |
hex | 1f3f3eb8e7 |
134205061351 has 4 divisors (see below), whose sum is σ = 134205797152. Its totient is φ = 134204325552.
The previous prime is 134205061343. The next prime is 134205061469. The reversal of 134205061351 is 153160502431.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 134205061351 - 23 = 134205061343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134205061051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133186 + ... + 534928.
It is an arithmetic number, because the mean of its divisors is an integer number (33551449288).
Almost surely, 2134205061351 is an apocalyptic number.
134205061351 is a deficient number, since it is larger than the sum of its proper divisors (735801).
134205061351 is an equidigital number, since it uses as much as digits as its factorization.
134205061351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 735800.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 134205061351 its reverse (153160502431), we get a palindrome (287365563782).
The spelling of 134205061351 in words is "one hundred thirty-four billion, two hundred five million, sixty-one thousand, three hundred fifty-one".
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