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1342103142143 = 1797497782917
BaseRepresentation
bin10011100001111011100…
…101001011111011111111
311202022012110211200101002
4103201323211023323333
5133442111401022033
62504315332040515
7165651365324051
oct23417345137377
94668173750332
101342103142143
11478201265035
1219813776313b
1399737ac7aba
1448d5b1bd8d1
1524da03953e8
hex1387b94beff

1342103142143 has 4 divisors (see below), whose sum is σ = 1349600925240. Its totient is φ = 1334605359048.

The previous prime is 1342103142137. The next prime is 1342103142161. The reversal of 1342103142143 is 3412413012431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1342103142143 - 232 = 1337808174847 is a prime.

It is a super-2 number, since 2×13421031421432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1342103142103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3748891280 + ... + 3748891637.

It is an arithmetic number, because the mean of its divisors is an integer number (337400231310).

Almost surely, 21342103142143 is an apocalyptic number.

1342103142143 is a deficient number, since it is larger than the sum of its proper divisors (7497783097).

1342103142143 is an equidigital number, since it uses as much as digits as its factorization.

1342103142143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7497783096.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1342103142143 its reverse (3412413012431), we get a palindrome (4754516154574).

The spelling of 1342103142143 in words is "one trillion, three hundred forty-two billion, one hundred three million, one hundred forty-two thousand, one hundred forty-three".

Divisors: 1 179 7497782917 1342103142143