13421125025051 has 4 divisors (see below), whose sum is σ = 13421140982400. Its totient is φ = 13421109067704.

The previous prime is 13421125025003. The next prime is 13421125025083. The reversal of 13421125025051 is 15052052112431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13421125025051 - 2⁶ = 13421125024987 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13421125024999 and 13421125025017.

It is not an unprimeable number, because it can be changed into a prime (13421125045051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6642491 + ... + 8424068.

It is an arithmetic number, because the mean of its divisors is an integer number (3355285245600).

Almost surely, 2^{13421125025051} is an apocalyptic number.

13421125025051 is a deficient number, since it is larger than the sum of its proper divisors (15957349).

13421125025051 is an equidigital number, since it uses as much as digits as its factorization.

13421125025051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15957348.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 13421125025051 its reverse (15052052112431), we get a palindrome (28473177137482).

The spelling of 13421125025051 in words is "thirteen trillion, four hundred twenty-one billion, one hundred twenty-five million, twenty-five thousand, fifty-one".