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1342142030113 = 10749925137041
BaseRepresentation
bin10011100001111101111…
…001100010000100100001
311202022022012000101122021
4103201331321202010201
5133442201324430423
62504323241341441
7165652350011053
oct23417571420441
94668265011567
101342142030113
11478221206155
12198148797881
1399742b92431
1448d624238d3
1524da39c795d
hex1387de62121

1342142030113 has 8 divisors (see below), whose sum is σ = 1357400268000. Its totient is φ = 1326934067520.

The previous prime is 1342142030101. The next prime is 1342142030149. The reversal of 1342142030113 is 3110302412431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1342142030113 - 213 = 1342142021921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1342142039113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12515128 + ... + 12621913.

It is an arithmetic number, because the mean of its divisors is an integer number (169675033500).

Almost surely, 21342142030113 is an apocalyptic number.

It is an amenable number.

1342142030113 is a deficient number, since it is larger than the sum of its proper divisors (15258237887).

1342142030113 is a wasteful number, since it uses less digits than its factorization.

1342142030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25137647.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1342142030113 its reverse (3110302412431), we get a palindrome (4452444442544).

The spelling of 1342142030113 in words is "one trillion, three hundred forty-two billion, one hundred forty-two million, thirty thousand, one hundred thirteen".

Divisors: 1 107 499 53393 25137041 2689663387 12543383459 1342142030113