Base | Representation |
---|---|
bin | 10011100001111101111… |
… | …011000100110011100111 |
3 | 11202022022012202221101212 |
4 | 103201331323010303213 |
5 | 133442201430401120 |
6 | 2504323254142035 |
7 | 165652353314120 |
oct | 23417573046347 |
9 | 4668265687355 |
10 | 1342142434535 |
11 | 478221461a91 |
12 | 19814895191b |
13 | 99742ca4536 |
14 | 48d624cb047 |
15 | 24da3a576c5 |
hex | 1387dec4ce7 |
1342142434535 has 16 divisors (see below), whose sum is σ = 1840686033216. Its totient is φ = 920309465088.
The previous prime is 1342142434511. The next prime is 1342142434537. The reversal of 1342142434535 is 5354342412431.
It is a cyclic number.
It is not a de Polignac number, because 1342142434535 - 28 = 1342142434279 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1342142434492 and 1342142434501.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1342142434537) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1780967 + ... + 2419943.
It is an arithmetic number, because the mean of its divisors is an integer number (115042877076).
Almost surely, 21342142434535 is an apocalyptic number.
1342142434535 is a deficient number, since it is larger than the sum of its proper divisors (498543598681).
1342142434535 is an equidigital number, since it uses as much as digits as its factorization.
1342142434535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 699002.
The product of its digits is 691200, while the sum is 41.
Adding to 1342142434535 its reverse (5354342412431), we get a palindrome (6696484846966).
The spelling of 1342142434535 in words is "one trillion, three hundred forty-two billion, one hundred forty-two million, four hundred thirty-four thousand, five hundred thirty-five".
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