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1342151425111 = 7191735917873
BaseRepresentation
bin10011100001111110011…
…101010111110001010111
311202022022211200201011011
4103201332131113301113
5133442211231100421
62504324214553051
7165652522610530
oct23417635276127
94668284621134
101342151425111
11478226542812
1219814b968787
1399744b017c3
1448d6378b687
1524da47314e1
hex1387e757c57

1342151425111 has 4 divisors (see below), whose sum is σ = 1533887342992. Its totient is φ = 1150415507232.

The previous prime is 1342151425057. The next prime is 1342151425123. The reversal of 1342151425111 is 1115241512431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1342151425111 - 213 = 1342151416919 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1342151425171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95867958930 + ... + 95867958943.

It is an arithmetic number, because the mean of its divisors is an integer number (383471835748).

Almost surely, 21342151425111 is an apocalyptic number.

1342151425111 is a deficient number, since it is larger than the sum of its proper divisors (191735917881).

1342151425111 is an equidigital number, since it uses as much as digits as its factorization.

1342151425111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191735917880.

The product of its digits is 4800, while the sum is 31.

Adding to 1342151425111 its reverse (1115241512431), we get a palindrome (2457392937542).

The spelling of 1342151425111 in words is "one trillion, three hundred forty-two billion, one hundred fifty-one million, four hundred twenty-five thousand, one hundred eleven".

Divisors: 1 7 191735917873 1342151425111