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13422114313 = 92391452767
BaseRepresentation
bin11001000000000010…
…10011011000001001
31021122102002001102221
430200001103120021
5204442030124223
610055510254041
7653420042416
oct144001233011
937572061387
1013422114313
115768485163
122727057321
13135b986b9a
1491484910d
15538532b5d
hex320053609

13422114313 has 4 divisors (see below), whose sum is σ = 13423576320. Its totient is φ = 13420652308.

The previous prime is 13422114289. The next prime is 13422114319. The reversal of 13422114313 is 31341122431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13422114313 - 213 = 13422106121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13422114319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 717145 + ... + 735622.

It is an arithmetic number, because the mean of its divisors is an integer number (3355894080).

Almost surely, 213422114313 is an apocalyptic number.

It is an amenable number.

13422114313 is a deficient number, since it is larger than the sum of its proper divisors (1462007).

13422114313 is an equidigital number, since it uses as much as digits as its factorization.

13422114313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1462006.

The product of its digits is 1728, while the sum is 25.

Adding to 13422114313 its reverse (31341122431), we get a palindrome (44763236744).

The spelling of 13422114313 in words is "thirteen billion, four hundred twenty-two million, one hundred fourteen thousand, three hundred thirteen".

Divisors: 1 9239 1452767 13422114313