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1342254066151 = 3736277136923
BaseRepresentation
bin10011100010000100100…
…100111010100111100111
311202022120222211102012011
4103202010210322213213
5133442414020104101
62504342322535051
7165655210212535
oct23420444724747
94668528742164
101342254066151
11478279478519
1219817a207487
139976015b44b
1448d73269155
1524dad758751
hex1388493a9e7

1342254066151 has 4 divisors (see below), whose sum is σ = 1378531203112. Its totient is φ = 1305976929192.

The previous prime is 1342254066113. The next prime is 1342254066157. The reversal of 1342254066151 is 1516604522431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1342254066151 - 221 = 1342251968999 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1342254066157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18138568425 + ... + 18138568498.

It is an arithmetic number, because the mean of its divisors is an integer number (344632800778).

Almost surely, 21342254066151 is an apocalyptic number.

1342254066151 is a deficient number, since it is larger than the sum of its proper divisors (36277136961).

1342254066151 is an equidigital number, since it uses as much as digits as its factorization.

1342254066151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36277136960.

The product of its (nonzero) digits is 172800, while the sum is 40.

Adding to 1342254066151 its reverse (1516604522431), we get a palindrome (2858858588582).

The spelling of 1342254066151 in words is "one trillion, three hundred forty-two billion, two hundred fifty-four million, sixty-six thousand, one hundred fifty-one".

Divisors: 1 37 36277136923 1342254066151