Base | Representation |
---|---|
bin | 11001000000001001… |
… | …00100001000110101 |
3 | 1021122110200111101201 |
4 | 30200010210020311 |
5 | 204442240010042 |
6 | 10055540452501 |
7 | 653430233365 |
oct | 144004441065 |
9 | 37573614351 |
10 | 13422969397 |
11 | 5768a09642 |
12 | 27273aa131 |
13 | 135bbc6156 |
14 | 9149cc9a5 |
15 | 5386511b7 |
hex | 320124235 |
13422969397 has 16 divisors (see below), whose sum is σ = 13951986048. Its totient is φ = 12904436160.
The previous prime is 13422969347. The next prime is 13422969431. The reversal of 13422969397 is 79396922431.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13422969397 is a prime.
It is a super-2 number, since 2×134229693972 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13422969317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1990243 + ... + 1996975.
It is an arithmetic number, because the mean of its divisors is an integer number (871999128).
Almost surely, 213422969397 is an apocalyptic number.
It is an amenable number.
13422969397 is a deficient number, since it is larger than the sum of its proper divisors (529016651).
13422969397 is an equidigital number, since it uses as much as digits as its factorization.
13422969397 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7500.
The product of its digits is 4408992, while the sum is 55.
The spelling of 13422969397 in words is "thirteen billion, four hundred twenty-two million, nine hundred sixty-nine thousand, three hundred ninety-seven".
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