Base | Representation |
---|---|
bin | 10011100010001000000… |
… | …000011010100100001111 |
3 | 11202022202000002202202210 |
4 | 103202020000122210033 |
5 | 133443023232402133 |
6 | 2504352140121503 |
7 | 165656506254015 |
oct | 23421000324417 |
9 | 4668660082683 |
10 | 1342311606543 |
11 | 4782a89a9466 |
12 | 198195536293 |
13 | 9976c056a0b |
14 | 48d7ab668b5 |
15 | 24db3822763 |
hex | 1388801a90f |
1342311606543 has 4 divisors (see below), whose sum is σ = 1789748808728. Its totient is φ = 894874404360.
The previous prime is 1342311606533. The next prime is 1342311606563. The reversal of 1342311606543 is 3456061132431.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1342311606543 - 25 = 1342311606511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1342311606523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223718601088 + ... + 223718601093.
It is an arithmetic number, because the mean of its divisors is an integer number (447437202182).
Almost surely, 21342311606543 is an apocalyptic number.
1342311606543 is a deficient number, since it is larger than the sum of its proper divisors (447437202185).
1342311606543 is an equidigital number, since it uses as much as digits as its factorization.
1342311606543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 447437202184.
The product of its (nonzero) digits is 155520, while the sum is 39.
Adding to 1342311606543 its reverse (3456061132431), we get a palindrome (4798372738974).
The spelling of 1342311606543 in words is "one trillion, three hundred forty-two billion, three hundred eleven million, six hundred six thousand, five hundred forty-three".
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