13423353324401 has 4 divisors (see below), whose sum is σ = 13455389967600. Its totient is φ = 13391316681204.

The previous prime is 13423353324361. The next prime is 13423353324431. The reversal of 13423353324401 is 10442335332431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13423353324401 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13423353324431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16018320971 + ... + 16018321808.

It is an arithmetic number, because the mean of its divisors is an integer number (3363847491900).

Almost surely, 2^{13423353324401} is an apocalyptic number.

It is an amenable number.

13423353324401 is a deficient number, since it is larger than the sum of its proper divisors (32036643199).

13423353324401 is an equidigital number, since it uses as much as digits as its factorization.

13423353324401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32036643198.

The product of its (nonzero) digits is 311040, while the sum is 38.

Adding to 13423353324401 its reverse (10442335332431), we get a palindrome (23865688656832).

The spelling of 13423353324401 in words is "thirteen trillion, four hundred twenty-three billion, three hundred fifty-three million, three hundred twenty-four thousand, four hundred one".