Base | Representation |
---|---|
bin | 11001000000001100… |
… | …10101100110001001 |
3 | 1021122111120002212201 |
4 | 30200012111212021 |
5 | 204442344342441 |
6 | 10055554440201 |
7 | 653434210306 |
oct | 144006254611 |
9 | 37574502781 |
10 | 13423434121 |
11 | 57691a6809 |
12 | 2727593061 |
13 | 135c029836 |
14 | 914ab00ad |
15 | 5386e3c31 |
hex | 320195989 |
13423434121 has 8 divisors (see below), whose sum is σ = 13628222720. Its totient is φ = 13218776208.
The previous prime is 13423434119. The next prime is 13423434149. The reversal of 13423434121 is 12143432431.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13423434121 - 21 = 13423434119 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13423434121.
It is not an unprimeable number, because it can be changed into a prime (13423434151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185320 + ... + 247366.
It is an arithmetic number, because the mean of its divisors is an integer number (1703527840).
Almost surely, 213423434121 is an apocalyptic number.
It is an amenable number.
13423434121 is a deficient number, since it is larger than the sum of its proper divisors (204788599).
13423434121 is an equidigital number, since it uses as much as digits as its factorization.
13423434121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65343.
The product of its digits is 6912, while the sum is 28.
Adding to 13423434121 its reverse (12143432431), we get a palindrome (25566866552).
The spelling of 13423434121 in words is "thirteen billion, four hundred twenty-three million, four hundred thirty-four thousand, one hundred twenty-one".
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