Base | Representation |
---|---|
bin | 1100001101010110100101… |
… | …1101101111011101010101 |
3 | 1202112021111201212210020212 |
4 | 3003111221131233131111 |
5 | 3224412403301013440 |
6 | 44314405023535205 |
7 | 2553550614054365 |
oct | 303255135573525 |
9 | 52467451783225 |
10 | 13423542204245 |
11 | 430598a694638 |
12 | 16096a515a505 |
13 | 764ab07c6914 |
14 | 3459baad69a5 |
15 | 18429cc93465 |
hex | c356976f755 |
13423542204245 has 16 divisors (see below), whose sum is σ = 16226734322160. Its totient is φ = 10659853392384.
The previous prime is 13423542204239. The next prime is 13423542204283. The reversal of 13423542204245 is 54240224532431.
It can be written as a sum of positive squares in 8 ways, for example, as 221488831876 + 13202053372369 = 470626^2 + 3633463^2 .
It is a cyclic number.
It is not a de Polignac number, because 13423542204245 - 240 = 12324030576469 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11949359 + ... + 13024371.
It is an arithmetic number, because the mean of its divisors is an integer number (1014170895135).
Almost surely, 213423542204245 is an apocalyptic number.
It is an amenable number.
13423542204245 is a deficient number, since it is larger than the sum of its proper divisors (2803192117915).
13423542204245 is a wasteful number, since it uses less digits than its factorization.
13423542204245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1093384.
The product of its (nonzero) digits is 921600, while the sum is 41.
Adding to 13423542204245 its reverse (54240224532431), we get a palindrome (67663766736676).
The spelling of 13423542204245 in words is "thirteen trillion, four hundred twenty-three billion, five hundred forty-two million, two hundred four thousand, two hundred forty-five".
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