Base | Representation |
---|---|
bin | 111110100000101100… |
… | …1000000101001010111 |
3 | 110211111111020111020022 |
4 | 1331001121000221113 |
5 | 4144411202431323 |
6 | 141400335455355 |
7 | 12461422124015 |
oct | 1750131005127 |
9 | 424444214208 |
10 | 134241061463 |
11 | 51a27641403 |
12 | 2202508755b |
13 | c874729262 |
14 | 66d684d8b5 |
15 | 375a3544c8 |
hex | 1f41640a57 |
134241061463 has 4 divisors (see below), whose sum is σ = 134982724968. Its totient is φ = 133499397960.
The previous prime is 134241061457. The next prime is 134241061477. The reversal of 134241061463 is 364160142431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 364160142431 = 401 ⋅908130031.
It is a cyclic number.
It is not a de Polignac number, because 134241061463 - 232 = 129946094167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134241061403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 370831481 + ... + 370831842.
It is an arithmetic number, because the mean of its divisors is an integer number (33745681242).
Almost surely, 2134241061463 is an apocalyptic number.
134241061463 is a deficient number, since it is larger than the sum of its proper divisors (741663505).
134241061463 is an equidigital number, since it uses as much as digits as its factorization.
134241061463 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 741663504.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 134241061463 in words is "one hundred thirty-four billion, two hundred forty-one million, sixty-one thousand, four hundred sixty-three".
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