Base | Representation |
---|---|
bin | 111110100000101100… |
… | …1010001110001001001 |
3 | 110211111111101001102201 |
4 | 1331001121101301021 |
5 | 4144411212202333 |
6 | 141400341200201 |
7 | 12461422535332 |
oct | 1750131216111 |
9 | 424444331381 |
10 | 134241131593 |
11 | 51a2768a068 |
12 | 22025100061 |
13 | c87475215a |
14 | 66d686b289 |
15 | 375a36a17d |
hex | 1f41651c49 |
134241131593 has 4 divisors (see below), whose sum is σ = 136244730640. Its totient is φ = 132237532548.
The previous prime is 134241131587. The next prime is 134241131617. The reversal of 134241131593 is 395131142431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 134241131593 - 29 = 134241131081 is a prime.
It is a super-2 number, since 2×1342411315932 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134241131503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1001799423 + ... + 1001799556.
It is an arithmetic number, because the mean of its divisors is an integer number (34061182660).
Almost surely, 2134241131593 is an apocalyptic number.
It is an amenable number.
134241131593 is a deficient number, since it is larger than the sum of its proper divisors (2003599047).
134241131593 is an equidigital number, since it uses as much as digits as its factorization.
134241131593 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2003599046.
The product of its digits is 38880, while the sum is 37.
The spelling of 134241131593 in words is "one hundred thirty-four billion, two hundred forty-one million, one hundred thirty-one thousand, five hundred ninety-three".
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