134241131081 has 2 divisors, whose sum is σ = 134241131082. Its totient is φ = 134241131080.

The previous prime is 134241131039. The next prime is 134241131093. The reversal of 134241131081 is 180131142431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132550605625 + 1690525456 = 364075^2 + 41116^2 .

It is an emirp because it is prime and its reverse (180131142431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134241131081 - 2¹⁴ = 134241114697 is a prime.

It is a super-2 number, since 2×134241131081² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134241131021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67120565540 + 67120565541.

It is an arithmetic number, because the mean of its divisors is an integer number (67120565541).

Almost surely, 2^134241131081 is an apocalyptic number.

It is an amenable number.

134241131081 is a deficient number, since it is larger than the sum of its proper divisors (1).

134241131081 is an equidigital number, since it uses as much as digits as its factorization.

134241131081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 29.

The spelling of 134241131081 in words is "one hundred thirty-four billion, two hundred forty-one million, one hundred thirty-one thousand, eighty-one".