Base | Representation |
---|---|
bin | 111110100000101111… |
… | …0000111101100011111 |
3 | 110211111120202112210211 |
4 | 1331001132013230133 |
5 | 4144412023313210 |
6 | 141400424313251 |
7 | 12461436403360 |
oct | 1750136075437 |
9 | 424446675724 |
10 | 134242401055 |
11 | 51a28376904 |
12 | 22025612827 |
13 | c874aa7c09 |
14 | 66d6abbb67 |
15 | 375a51b38a |
hex | 1f41787b1f |
134242401055 has 16 divisors (see below), whose sum is σ = 184330911744. Its totient is φ = 91938408480.
The previous prime is 134242401031. The next prime is 134242401103. The reversal of 134242401055 is 550104242431.
134242401055 is digitally balanced in base 11, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 134242401055 - 211 = 134242399007 is a prime.
It is a super-2 number, since 2×1342424010552 (a number of 23 digits) contains 22 as substring.
134242401055 is strictly pandigital in base 11.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2336287 + ... + 2393056.
It is an arithmetic number, because the mean of its divisors is an integer number (11520681984).
Almost surely, 2134242401055 is an apocalyptic number.
134242401055 is a deficient number, since it is larger than the sum of its proper divisors (50088510689).
134242401055 is an equidigital number, since it uses as much as digits as its factorization.
134242401055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4730166.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 134242401055 its reverse (550104242431), we get a palindrome (684346643486).
The spelling of 134242401055 in words is "one hundred thirty-four billion, two hundred forty-two million, four hundred one thousand, fifty-five".
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