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134242401055 = 578114729343
BaseRepresentation
bin111110100000101111…
…0000111101100011111
3110211111120202112210211
41331001132013230133
54144412023313210
6141400424313251
712461436403360
oct1750136075437
9424446675724
10134242401055
1151a28376904
1222025612827
13c874aa7c09
1466d6abbb67
15375a51b38a
hex1f41787b1f

134242401055 has 16 divisors (see below), whose sum is σ = 184330911744. Its totient is φ = 91938408480.

The previous prime is 134242401031. The next prime is 134242401103. The reversal of 134242401055 is 550104242431.

134242401055 is digitally balanced in base 11, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 134242401055 - 211 = 134242399007 is a prime.

It is a super-2 number, since 2×1342424010552 (a number of 23 digits) contains 22 as substring.

134242401055 is strictly pandigital in base 11.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2336287 + ... + 2393056.

It is an arithmetic number, because the mean of its divisors is an integer number (11520681984).

Almost surely, 2134242401055 is an apocalyptic number.

134242401055 is a deficient number, since it is larger than the sum of its proper divisors (50088510689).

134242401055 is an equidigital number, since it uses as much as digits as its factorization.

134242401055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4730166.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 134242401055 its reverse (550104242431), we get a palindrome (684346643486).

The spelling of 134242401055 in words is "one hundred thirty-four billion, two hundred forty-two million, four hundred one thousand, fifty-five".

Divisors: 1 5 7 35 811 4055 5677 28385 4729343 23646715 33105401 165527005 3835497173 19177485865 26848480211 134242401055