Base | Representation |
---|---|
bin | 1100001101011001001110… |
… | …1101101011100010010001 |
3 | 1202112100100010122122021220 |
4 | 3003112103231223202101 |
5 | 3224420331230304203 |
6 | 44315003224235253 |
7 | 2553604311665664 |
oct | 303262355534221 |
9 | 52470303578256 |
10 | 13424251025553 |
11 | 4306213809575 |
12 | 160986260bb29 |
13 | 764b94604204 |
14 | 345a46cc96db |
15 | 1842e0109653 |
hex | c3593b6b891 |
13424251025553 has 64 divisors (see below), whose sum is σ = 18641511383040. Its totient is φ = 8583809299200.
The previous prime is 13424251025543. The next prime is 13424251025651. The reversal of 13424251025553 is 35552015242431.
13424251025553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13424251025553 - 29 = 13424251025041 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13424251025543) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8200519051 + ... + 8200520687.
It is an arithmetic number, because the mean of its divisors is an integer number (291273615360).
Almost surely, 213424251025553 is an apocalyptic number.
It is an amenable number.
13424251025553 is a deficient number, since it is larger than the sum of its proper divisors (5217260357487).
13424251025553 is a wasteful number, since it uses less digits than its factorization.
13424251025553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3278.
The product of its (nonzero) digits is 720000, while the sum is 42.
Adding to 13424251025553 its reverse (35552015242431), we get a palindrome (48976266267984).
The spelling of 13424251025553 in words is "thirteen trillion, four hundred twenty-four billion, two hundred fifty-one million, twenty-five thousand, five hundred fifty-three".
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