Base | Representation |
---|---|
bin | 10011100010001111110… |
… | …010010010001101101001 |
3 | 11202100002002200112122001 |
4 | 103202033302102031221 |
5 | 133443310140320131 |
6 | 2504413121331001 |
7 | 165662652513601 |
oct | 23421762221551 |
9 | 4670062615561 |
10 | 1342442120041 |
11 | 478365641160 |
12 | 198211196a61 |
13 | 997900c2139 |
14 | 48d9021bc01 |
15 | 24dc0003261 |
hex | 1388fc92369 |
1342442120041 has 32 divisors (see below), whose sum is σ = 1501820559360. Its totient is φ = 1189414665600.
The previous prime is 1342442120021. The next prime is 1342442120099. The reversal of 1342442120041 is 1400212442431.
It is a cyclic number.
It is not a de Polignac number, because 1342442120041 - 223 = 1342433731433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1342442119991 and 1342442120009.
It is not an unprimeable number, because it can be changed into a prime (1342442120021) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 701746101 + ... + 701748013.
It is an arithmetic number, because the mean of its divisors is an integer number (46931892480).
Almost surely, 21342442120041 is an apocalyptic number.
1342442120041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1342442120041 is a deficient number, since it is larger than the sum of its proper divisors (159378439319).
1342442120041 is a wasteful number, since it uses less digits than its factorization.
1342442120041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4437.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 1342442120041 its reverse (1400212442431), we get a palindrome (2742654562472).
The spelling of 1342442120041 in words is "one trillion, three hundred forty-two billion, four hundred forty-two million, one hundred twenty thousand, forty-one".
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