Base | Representation |
---|---|
bin | 1100001101011010001011… |
… | …0111010101000010110111 |
3 | 1202112100222211221201001220 |
4 | 3003112202313111002313 |
5 | 3224421341313304421 |
6 | 44315044344321423 |
7 | 2553613516361406 |
oct | 303264267250267 |
9 | 52470884851056 |
10 | 13424505213111 |
11 | 4306334242433 |
12 | 1609913773273 |
13 | 764c05181955 |
14 | 345a6c97563d |
15 | 1843075b93c6 |
hex | c35a2dd50b7 |
13424505213111 has 4 divisors (see below), whose sum is σ = 17899340284152. Its totient is φ = 8949670142072.
The previous prime is 13424505213089. The next prime is 13424505213173. The reversal of 13424505213111 is 11131250542431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13424505213111 - 26 = 13424505213047 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13424505217111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2237417535516 + ... + 2237417535521.
It is an arithmetic number, because the mean of its divisors is an integer number (4474835071038).
Almost surely, 213424505213111 is an apocalyptic number.
13424505213111 is a deficient number, since it is larger than the sum of its proper divisors (4474835071041).
13424505213111 is an equidigital number, since it uses as much as digits as its factorization.
13424505213111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4474835071040.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 13424505213111 its reverse (11131250542431), we get a palindrome (24555755755542).
The spelling of 13424505213111 in words is "thirteen trillion, four hundred twenty-four billion, five hundred five million, two hundred thirteen thousand, one hundred eleven".
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