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13424535141 = 34474845047
BaseRepresentation
bin11001000000010101…
…00010011001100101
31021122120122001012020
430200022202121211
5204443140111031
610100034213353
7653446444263
oct144012423145
937576561166
1013424535141
115769888a46
122727a24259
13135c323a24
14914cb9433
15538860096
hex3202a2665

13424535141 has 4 divisors (see below), whose sum is σ = 17899380192. Its totient is φ = 8949690092.

The previous prime is 13424535119. The next prime is 13424535149. The reversal of 13424535141 is 14153542431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13424535141 - 25 = 13424535109 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13424535149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2237422521 + ... + 2237422526.

It is an arithmetic number, because the mean of its divisors is an integer number (4474845048).

Almost surely, 213424535141 is an apocalyptic number.

It is an amenable number.

13424535141 is a deficient number, since it is larger than the sum of its proper divisors (4474845051).

13424535141 is an equidigital number, since it uses as much as digits as its factorization.

13424535141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4474845050.

The product of its digits is 28800, while the sum is 33.

The spelling of 13424535141 in words is "thirteen billion, four hundred twenty-four million, five hundred thirty-five thousand, one hundred forty-one".

Divisors: 1 3 4474845047 13424535141