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1342503400551 = 3447501133517
BaseRepresentation
bin10011100010010011011…
…100000011010001100111
311202100020100222220200120
4103202103130003101213
5133443421332304201
62504423151013023
7165664325423145
oct23422334032147
94670210886616
101342503400551
11478397197105
1219822980a173
139979c9c9bb1
1448d98410595
1524dc55aa536
hex13893703467

1342503400551 has 4 divisors (see below), whose sum is σ = 1790004534072. Its totient is φ = 895002267032.

The previous prime is 1342503400523. The next prime is 1342503400559. The reversal of 1342503400551 is 1550043052431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1342503400551 - 210 = 1342503399527 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1342503400559) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223750566756 + ... + 223750566761.

It is an arithmetic number, because the mean of its divisors is an integer number (447501133518).

Almost surely, 21342503400551 is an apocalyptic number.

1342503400551 is a deficient number, since it is larger than the sum of its proper divisors (447501133521).

1342503400551 is an equidigital number, since it uses as much as digits as its factorization.

1342503400551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447501133520.

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 1342503400551 its reverse (1550043052431), we get a palindrome (2892546452982).

The spelling of 1342503400551 in words is "one trillion, three hundred forty-two billion, five hundred three million, four hundred thousand, five hundred fifty-one".

Divisors: 1 3 447501133517 1342503400551