134250441440341 has 4 divisors (see below), whose sum is σ = 134340602920300. Its totient is φ = 134160279960384.

The previous prime is 134250441440293. The next prime is 134250441440407. The reversal of 134250441440341 is 143044144052431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 82535789576241 + 51714651864100 = 9084921^2 + 7191290^2 .

It is a cyclic number.

It is not a de Polignac number, because 134250441440341 - 2¹¹ = 134250441438293 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134250441440294 and 134250441440303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134250441440441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45080737746 + ... + 45080740723.

It is an arithmetic number, because the mean of its divisors is an integer number (33585150730075).

Almost surely, 2^{134250441440341} is an apocalyptic number.

It is an amenable number.

134250441440341 is a deficient number, since it is larger than the sum of its proper divisors (90161479959).

134250441440341 is an equidigital number, since it uses as much as digits as its factorization.

134250441440341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90161479958.

The product of its (nonzero) digits is 368640, while the sum is 40.

Adding to 134250441440341 its reverse (143044144052431), we get a palindrome (277294585492772).

The spelling of 134250441440341 in words is "one hundred thirty-four trillion, two hundred fifty billion, four hundred forty-one million, four hundred forty thousand, three hundred forty-one".