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13425054133 = 25795205527
BaseRepresentation
bin11001000000011001…
…00001000110110101
31021122121121102010011
430200030201012311
5204443303213013
610100053300221
7653454035341
oct144014410665
937577542104
1013425054133
11576a102967
122728034671
13135c47601a
14914db2621
15538913c3d
hex3203211b5

13425054133 has 4 divisors (see below), whose sum is σ = 13430262240. Its totient is φ = 13419846028.

The previous prime is 13425054119. The next prime is 13425054163. The reversal of 13425054133 is 33145052431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13425054133 - 25 = 13425054101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13425054095 and 13425054104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13425054163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2600185 + ... + 2605342.

It is an arithmetic number, because the mean of its divisors is an integer number (3357565560).

Almost surely, 213425054133 is an apocalyptic number.

It is an amenable number.

13425054133 is a deficient number, since it is larger than the sum of its proper divisors (5208107).

13425054133 is an equidigital number, since it uses as much as digits as its factorization.

13425054133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5208106.

The product of its (nonzero) digits is 21600, while the sum is 31.

The spelling of 13425054133 in words is "thirteen billion, four hundred twenty-five million, fifty-four thousand, one hundred thirty-three".

Divisors: 1 2579 5205527 13425054133